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Simple Gliders in the Science and Mathematics Curriculum
Gary Hinze
2005
Simple gliders allow you to have fun with basic concepts of science and mathematics. A teacher can go as far as desired,
depending on the level of their students. Having a contest using a measuring tape to see how far balsa or paper gliders will
fly is only a beginning. Adding a stopwatch to the measuring tape lets you time the flights and show the kids how to measure
speed. Ask the kids how fast their car goes or what is the speed limit. They will answer in miles per hour. State that speed is
measured in units of distance per unit of time. It tells you how far you will go in a certain amount of time. Miles are a measure
of distance and hours are a measure of time. The measuring tape measures distance in feet and the stopwatch measures
time in seconds. With them, you can measure speed in different units, feet per second. You can have the kids fly the gliders,
measure the distance with the tape, time the flight with the stopwatch and record the figures. They can divide the distance by
the time, longhand or with a calculator, to get the glider’s speed over the ground in feet per second. That may be as far as you
would want to go with fourth graders.
Unit Conversion - Converting Feet Per Second to Miles Per Hour
5,280 feet in one mile - 60 seconds in a minute – 60 minutes in an hour or 3,600 seconds in an hour
If the students are ready you can continue with the conversion to miles per hour. There are 5,280 feet in a mile. There are 60
seconds in a minute and 60 minutes in an hour, so there are 3,600 seconds in an hour. To convert feet per second to miles
per hour, you convert feet to miles by dividing by 5,280 and convert per second to per hour by multiplying by 3,600. This has
the same result as multiplying by 0.68181.... Another way to remember this is that 60 miles per hour is 88 feet per second, or
15 miles per hour is 22 feet per second. The speed in miles per hour will always be less than the speed in feet per second by
the same ratio, so you can convert speed in feet per second by dividing it by 22 and multiplying it by 15 to get miles per hour.
To go from miles per hour to feet per second, multiply by 22 and divide by 15, or simply multiply by 1.466....
Rate of Descent
If the kids fly their gliders in a straight, steadily descending line, you can also measure the height of the launch and calculate
the lift to drag ratio, the glide angle and the rate of descent. The rate of descent is the rate at which the glider loses altitude.
It is a speed and is measured in feet per second. This time you divide the height of launch by the time of flight. The rate of
descent is important to glider pilots because it tells them how fast a current of air must rise to keep them flying. If a current
of air rises as fast as the glider’s rate of descent, the glider will not loose altitude. If a current of air rises faster than the
glider’s rate of descent, the glider will go up higher. If you fly your glider in still air, you can estimate its' maximum altitude
by measuring its' time of descent and multiplying that by its' measured rate of descent.
Glide Angle
The glide angle is the acute angle the glider’s flight path makes with the horizontal floor. The angle can be measured by
making a scale drawing of the gliders flight triangle. The horizontal leg of the triangle will represent the distance traveled
over the floor and the vertical leg will represent how high the glider was above the floor when launched. This is best done
with an engineer’s scale, having various divisions of an inch. With school rulers, it might be best to let 1/4" on the drawing
represent one foot of actual distance, or whatever it takes to fit the diagram onto a sheet of paper. Quadruled paper makes
this easy.
If the glider was launched 4' above the floor, that distance would be represented by a 4 x 1/4" = 1" vertical line on the scale
drawing. If it flew 20 feet, that distance would be represented by a 20 x 1/4" = 5" horizontal line on the drawing. Now draw in
the hypotenuse, representing the glider’s flight path, and use a protractor to measure the angle between the horizontal line
and the hypotenuse, in this case 11 degrees. (This can also be calculated from the distances, since the ratio of the height to
the distance is the tangent of the angle. In my school days, we would look this up in trig tables, but today scientific calculators
are widely available and you can find the angle as the arctangent of 4'/20' or 0.2, which works out to 11.31 degrees.) This is
known as the glide angle. You can also measure the length of the hypotenuse and find the distance the glider traveled through
the air, in this case 5.1 inch on the drawing, corresponding to 4 x 5.1 = 20.4 feet. This shows that the distance the glider flew
through the air is a little greater than the distance it traveled over the ground. (This distance can also be calculated from the
theorem of Pythagoras as the square root of the sum of the squares of the other two sides, easy to do with today’s scientific
calculators.)
Calculating Airspeed
This allows estimation of the glider’s speed through the air. Divide the distance traveled through the air by the time of flight to
get the glider’s speed through the air. Assume the time of flight was 3 seconds. The speed through the air is then 20.4 / 3 = 6.8
feet per second. You notice that this speed is different from the speed over the ground, because the distances are different.
Both of these differ from the descent rate for the same reason.
Forces of Glide
In a steady glide the weight of the glider pulls it downward along an inclined path and the air flowing over the glider produces
an aerodynamic force that is equal and opposite to the weight.
Lift to Drag Ratio
The aerodynamic force may be resolved into two components. Lift is defined as the component that acts perpendicular to the
flight path in an upward direction. Drag is defined as the component that acts parallel to the flight path opposite to the direction
of flight. The lift to drag ratio is numerically the same as the ratio of the distance traveled horizontally to the height descended.
This is because the weight acts parallel to the height, the drag acts parallel with the flight path and the lift acts perpendicular to
the flight path, tying these triangles together. In the hypothetical case here, it would be 20' / 4' = 5. This is important to a glider
pilot because it tells how far the glider will go from a given altitude. It helps the pilot decide when to head home.
Force Diagram
This is just the ratio of the lift to the drag. It doesn’t tell us what the actual forces are. To do that we need something that
establishes a scale of force. Lift and drag are forces. The weight of the glider is the force that establishes the scale of the
diagram of forces, so a balance is required to weigh the glider.
The triangle of forces is geometrically similar to the glide triangle. You can see this by drawing the glide triangle, as above, and
plotting the lift, drag and weight forces acting on a point along the hypotenuse. Pick any point about midway along the hypotenuse
of the glide triangle. This point represents the glider’s position at some time. In our example we know that the drag force is one
unit long for every five units of the lift force. Draw an arrow 1/4" long pointing uphill along the glide path from the point. This
represents the drag force. Draw an arrow perpendicular to the hypotenuse, pointing upwards, 5 times as long as the drag arrow,
or 11/4" long. This arrow represents the lift force. These two arrows form two sides of a rectangle. Carefully draw in the other two
sides of that rectangle. Now draw in the diagonal of the rectangle that passes through the original point. This diagonal will be vertical.
This diagonal represents the total aerodynamic force that acts on the glider and it is equal and opposite to the weight force in
a steady glide. The triangles formed by the diagonal within the rectangle are geometrically similar to the glide triangle. Both
triangles have the same angles. Corresponding sides are in the same ratio to each other. In particular, the lift (long side of force
triangle) is to the weight (hypotenuse of force triangle) as the horizontal distance covered (long side of flight path triangle) is to the
flight path length (hypotenuse of flight path triangle). Let’s assume the glider weighs 10.2 grams.
If the 10.2 grams of the glider’s weight corresponds to the 5.1 inches of the scale drawing of the flight path, then the lift must
be 10 grams to correspond to the 5 inches of the scale drawing of the horizontal distance covered. The ratio is two to one.
This can be expressed algebraically, and it can be expressed in terms of the original measured distances. We also know that
the drag is one fifth of the lift, so it must be 2 grams. This establishes a scale for our force diagram of 2 grams per quarter inch
or 8 grams per inch. The scale force diagram is known as a vector diagram. The arrows representing the forces are known as
vectors and weight is the vector sum of lift and drag. A vector is a mathematical entity that has both magnitude and direction,
just like forces.
Gravitational Energy of Glider
A glider uses gravitational energy to fly. Gravity doesn’t just pull the glider down, it also pulls it against air resistance. Gravity
powers the glider. From the information we have, we can calculate the energy and power provided by gravity.
Definition of Work
When you lift a weight, you do work. When you lift twice as much weight, you do twice as much work. When you lift the weight
twice as far, you do twice as much work. Work is energy. Energy has units of a force (weight) times a distance (height). The
energy that the glider had at the top of its path, relative to the ground, is the weight of the glider times its height above the floor.
That’s how much energy it would take to lift it that high and that’s how much energy it takes for it to fly against air resistance on
the way down.
Energy Units and Conversion
Energy may be expressed in different units, depending on what units were used to measure the weight and the distance.
In the example above we had a 10.2 gram glider launched 4 feet above the floor. This would result in an energy value of 1
0.2 x 4 = 40.8 gram feet. It is more usual to express energy in foot pounds. There are 453.59 grams in a pound, so we must
divide 40.8 gram feet by 453.59 grams per pound to get 0.0899 foot pounds of energy. Gravity expended that much energy to
bring the glider down to the floor.
Calculating Horsepower
Power is the rate at which energy is expended. We know how long it took for that 0.0899 foot pounds of energy to be
expended because we timed the flight. Let’s assume the flight lasted 3 seconds. Then we know that energy was expended at
a rate of 0.0889 foot pounds in 3 seconds, or 0.0899 / 3 = 0.0300 foot pounds per second. It is more usual to hear power
expressed in horse power. One horse power is 550 foot pounds per second, so we must divide 0.0300 foot pounds per
second by 550 foot pounds per second per horsepower to get 0.0000545 horsepower.
Gravity pulled the glider against air resistance. We measured the air resistance as 2 grams of drag. We also measured
the distance the glider moved through the air against that drag, 20.4 feet. The amount of energy expended by gravity pulling
the glider against the drag is the force times the distance, or 2 grams x 20.4 feet = 40.8 gram feet, the same as we got before.
This took the same 3 seconds, so the horsepower is also the same when calculated this way. The interesting thing about this
way of calculating the power is that we multiplied the drag force by the length of the flight path and divided by the time of flight.
But the length of the flight path divided by the time of flight is the glider’s airspeed. This tells us that another way to calculate the
power of a glider is to multiply its’ drag by its’ airspeed.
Science and Math Lessons from Simple Gliders
This illustrates how simple gliders can motivate a discussion of measurement, length, time, speed, unit conversion, ratio,
angle, relative speed, piloting, scale, scale drawing, graphical solution, right triangles, angle tangent, Pythagorean theorem,
weight, force, force diagram, vectors, vector addition, geometrical similarity, energy, rate and power. It also illustrates how
scientific concepts begin with simple operational definitions in measurement processes and are elaborated through geometrical
and algebraic manipulation. You can draw a flow diagram showing how the measured quantities lead to the derived quantities.
With four simple measuring tools, a tape, a protractor, a stopwatch and a balance, we have measured four quantities and
derived ten. We have demonstrated numerical and graphical solution methods.
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